3x^2-25x-368=0

Solution for 3x^2-25x-368=0 equation:

3x^2-25x-368=0

a = 3; b = -25; c = -368;
Δ = b2-4ac
Δ = -252-4·3·(-368)
Δ = 5041
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5041}=71$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-71}{2*3}=\frac{-46}{6}
=-7+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+71}{2*3}=\frac{96}{6}
=16
$